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C ISA2+pooncerelease+poacquirerelease+poacquireonce (* * Result: Never * * This litmus test demonstrates that a release-acquire chain suffices * to order P0()'s initial write against P2()'s final read. The reason * that the release-acquire chain suffices is because in all but one * case (P2() to P0()), each process reads from the preceding process's * write. In memory-model-speak, there is only one non-reads-from * (AKA non-rf) link, so release-acquire is all that is needed. *) {} P0(int *x, int *y) { WRITE_ONCE(*x, 1); smp_store_release(y, 1); } P1(int *y, int *z) { int r0; r0 = smp_load_acquire(y); smp_store_release(z, 1); } P2(int *x, int *z) { int r0; int r1; r0 = smp_load_acquire(z); r1 = READ_ONCE(*x); } exists (1:r0=1 /\ 2:r0=1 /\ 2:r1=0) |